Sulphur has highest oxidation state in

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
Solution:Correct option is b).
$* S O_{2} = + 4$
$H_{2} * S O_{4} = + 6$
$N a_{2} {* S}_{2} O_{3} = + 2$
$N a_{2} {* S}_{4} O_{6} = + \frac{5}{2}$

Suggest Corrections

Similar questions

-

H_{2} S O_{4}

-

H_{2} S O_{4}

The highest stable oxidation state exhibited by sulphur in its compounds is:

Join BYJU'S Learning Program