Sulphur has highest oxidation state in

S O_{2}

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H_{2} S O_{4}

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N a_{2} S_{2} O_{3}

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N a_{2} S_{4} O_{6}

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Solution

The correct option is B $H_{2} S O_{4}$
Solution:Correct option is b).
$* S O_{2} = + 4$
$H_{2} * S O_{4} = + 6$
$N a_{2} {* S}_{2} O_{3} = + 2$
$N a_{2} {* S}_{4} O_{6} = + \frac{5}{2}$

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H_{2} S O_{4}

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The highest stable oxidation state exhibited by sulphur in its compounds is:

Which of the following oxy acid of sulphur has +6 oxidation state for sulphur?

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