Question

Sulphur reacts with chlorine in $1:2$ ratio and forms $X$. hydrolysis of $X$ gives a sulphur compound $Y$. What is the hybridization state of central atom in the compound?

• A. $s{p}^3$
• B. $s{p}^2$
• C. $sp$
• D. $ds{p}^2$

Answer 1

The correct option is A $s{p}^3$

The reaction of sulphur with chlorine in the ratio 1:2

so, $S+2C{l}_2\to SC{l}_4$

x

Hydrolysis of X gives

$SC{l}_4+4H_{2}O\to S(OH{)}_4+4HClS(OH{)}_4⟶H_{2}S{O}_3+H_{2}O$

Y

Hybridisation of Sulphur in $S{O}_3$ is $S{P}_3$