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Question

Sulphur trioxide is dissolved in heavy water to form a compound X. The state of hybridisation of sulphur in X is:

A
sp2
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B
sp3
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C
sp
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D
dsp2
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Solution

The correct option is A sp3
Hybridisation is given by the following formula:
H=V+XC+A2

Here, V= number of valence electrons in central atom, X= number of monovalent atoms around the central atom, C= positive charge on cation and A= negative charge on anion.
If H=2, then the compound is sp hybridised.
If H=3, then the compound is sp2 hybridised.
If H=4, then the compound is sp3 hybridised.
If H=5, then the compound is sp3d hybridised.
If H=6, then the compound is sp3d2 hybridised.
If H=7, then the compound is sp3d3 hybridised.

Sulphur trioxide dissolves in heavy water to form sulphuric acid.
SO3+D2OD2SO4

So, its hybridisation (H)=(6+20+0)2=4
Hence, the state of hybridisation is sp3.

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