Question

Sulphur vapours $\left(S_n\right)$ diffuses through a porous plug at the 0.354 rate of diffusion of $O_2$ gas under similar condition of $P$ and $T$. The value of $n$ is:

• A. 2
• B. 4
• C. 6
• D. 8

Answer 1

The correct option is D 8

As we know,
$r_1/r_2=\sqrt{M_2/M_1}$
$\frac{r_{S_n}}{r_{O_2}}=\sqrt{\frac{M_{O_2}}{M_{S_n}}}$
$\therefore 0.354=\sqrt{\frac{32}{M_{S_n}}}$
$\therefore M_{S_n}=255.38$
also as we know, $S$ has molar mass of 32.
$n\times 32=255.8$
$n=8$