Question

Sulphuric acid is not used for preparation of original solution in analysis of basic radicals because ?

• A. It is a reducing agent
• B. It forms insoluble sulphate with certain basic radicals
• C. It forms a soluble complex
• D. It is oxidizing in nature

Answer 1

Answer: (B), (D)

The correct options are
B It forms insoluble sulphate with certain basic radicals
D It is oxidizing in nature

Sulphuric acid is not used for the preparation of the original solution in analysis of the basic radicals because:

$B:$ It forms insoluble sulphates with certain basic radicals.

$D:$ It is oxidizing in nature.

Dilute sulfuric acid reacts with metals via a single displacement reaction as with other typical acids producing $H_2$ gas and salts (the metal sulfate). It attacks reactive metals (metals at positions above $Cu$ in the reactivity series) such as $Fe,Al,Zn,Mg$ and $Ni$.

$Fe\left(s\right)+H_{2}S{O}_4\left(aq\right)\to H_2\left(g\right)+FeS{O}_4\left(aq\right)$

So, the corret options are $B$ and $D$