Sulphuryl chloride $(S O_{2} C l_{2})$ reacts with white phosphorus $(P_{4})$ to give:

P C l_{5}, S O_{2}

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O P C l_{3}, S O C l_{2}

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P C l_{5}, S O_{2}, S_{2} C l_{2}

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O P C l_{3}, S O_{2}, S_{2} C l_{2}

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Solution

The correct option is D $P C l_{5}, S O_{2}$
Sulphuryl chloride ( $S O_{2} C l_{2}$ ) reacts with white phosphorus ( $P_{4}$ ) to give phosphorous pentachloride and sulphur dioxide.

$10 S O_{2} C l_{2} + P_{4} \to 4 P C l_{5} + 10 S O_{2}$

Hence, option A is correct.

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Similar questions

Q. Paragraph 2
The reactions of

C l_{2}

gas with cold-dilute and hot-concentrated NaOH in water give soduum salts fo two different oxoacids of chlorine, P and Q, respectively. The

C l_{2}

gas reacts with

S O_{2}

gas, in presence of charcoal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus.

4. R, S and T, respectively, are
(IIT-JEE, 2013)

Q. The reaction of

C l_{2}

gas with cold dilute and hot concentrated NaOH in water give sodium salt of two (different) oxoacids of chlorine P and Q respectively. The

C l_{2}

gas reacts with

S O_{2}

gas, in presence of charcoal to give a product R. R reacts with white phosphorous to give a compound S. On hydrolysis, S gives an oxoacid of phosphorous T.
R, S and T, respectively are:

$S O_{2}$ reacts with $C l_{2}$ in sunlight to form

Q. Among the following, choose the compounds that can react with

P C l_{5}

to give

P O C l_{3}

$P_{4}$ (white phosphorus) when treated with thionyl chloride produces phosphorus ___. On the other hand if $P_{4}$ (white phosphorus) is treated with sulphuryl chloride we get phosphorus ___.

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Sulphuryl chloride (SO2Cl2) reacts with white phosphorus (P4) to give:

The correct option is D PCl5,SO2Sulphuryl chloride (SO2Cl2) reacts with white phosphorus (P4) to give phosphorous pentachloride and sulphur dioxide.10SO2Cl2+P4→4PCl5+10SO2Hence, option A is correct.

Sulphuryl chloride $(S O_{2} C l_{2})$ reacts with white phosphorus $(P_{4})$ to give:

The correct option is D $P C l_{5}, S O_{2}$
Sulphuryl chloride ( $S O_{2} C l_{2}$ ) reacts with white phosphorus ( $P_{4}$ ) to give phosphorous pentachloride and sulphur dioxide.

$10 S O_{2} C l_{2} + P_{4} \to 4 P C l_{5} + 10 S O_{2}$

Hence, option A is correct.