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Question

Sum 2,314,412, ..... to 20 terms.

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Solution

Given series is 2,314,412,....... upto 20 terms
The given series can be written as 84,134,184,..... to 20 terms
14(8+13+18+......) to 20 terms
Observe that 8,13,18..... is in Arithmetic Progression with 8 as first term and 5 as common difference.
So, the sum of first 20 terms in that series will be 14(202(2×8+(201)×5))=14(1110)=5552

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