∑fixi=6Y−4 and ∑fi=8. If the mean of the distribution is 7, what is the value of Y?
∵Mean=ΣfixiΣfi
⇒7=6Y−48
⇒6Y – 4 = 7 x 8 = 56 ⇒6Y = 56 + 4 = 60 ⇒Y = 10