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Byju's Answer
Standard XII
Mathematics
Combination
∑n-1r=0nCrnCr...
Question
∑
r
=
0
n
−
1
n
C
r
n
C
r
+
n
C
r
+
1
=
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Solution
∑
r
=
1
n
=
1
n
C
r
[
n
C
r
+
n
C
(
r
+
1
)
]
⇒
1
C
o
1
C
o
+
1
C
1
=
1
+
1
1
+
1
=
1
2
[
∵
n
C
o
=
n
C
n
=
1
]
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Similar questions
Q.
If
n
∑
r
=
0
(
n
C
r
−
1
n
C
r
+
n
C
r
−
1
)
3
=
25
24
,
then the value of
n
is
Q.
n
C
r
+
n
C
r
−
1
is equal to