-nj-1-ni-1i is equal to

The correct option is C n^2(n+1)2 Given, ∑ _j=1^n∑ _i=1^ni here, we use the direct formula =∑ _j=1^n12n(n+1) =12n^2(n+1) =n^2(n+1)2 ...

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Complex Numbers

∑nj=1∑ni=1i i...

Question

$\sum_{j = 1}^{n} \sum_{i = 1}^{n} i$ is equal to

\frac{n (n + 1)}{2}

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\frac{n (n + 1)^{2}}{2}

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\frac{n^{2} (n + 1)}{2}

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none of these

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Solution

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