Sum of 2 number is 108. If one exceeds the other by 42. Find the number

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Solution

Take one number= x
then second number= x+42
we know sum of 2 number=108
so, x+(x+42)=108
2x+42=108
2x=108-42=66
x=66/2 =33
so,second number=x+42=33+42
=75
so the numbers are 33 and 75

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