Sum of 4 consecutive odd numbers is 80. Find the product of the highest and lowest numbers out of those 4.

391

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

315

No worries! We‘ve got your back. Try BYJU‘S free classes today!

475

No worries! We‘ve got your back. Try BYJU‘S free classes today!

247

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 391
Let the numbers be $a - 3, a - 1, a + 1, a + 3$ .
Given: Sum = 80
$= a - 3 + a - 1 + a + 1 + a + 3 = 80 \Rightarrow 4 a = 80 \Rightarrow a = 20$
Highest $= 20 + 3 = 23$
Lowest $= 20 - 3 = 17$
Product $= 17 \times 23 = 391$

Suggest Corrections

Similar questions

If twice the sum of 5 consecutive odd numbers and thrice the sum of 4 consecutive even numbers is 178 and thrice the sum of 5 consecutive odd numbers and twice the sum of 4 consecutive even numbers is 177, then find the biggest odd number.

Twice the sum of 5 consecutive odd numbers and thrice the sum of 4 consecutive even numbers is 178. Thrice the sum of 5 consecutive odd numbers and twice the sum of 4 consecutive even numbers is 177. The difference between the sum of 5 consecutive odd numbers and 4 consecutive even numbers is

Join BYJU'S Learning Program

Sum of 4 consecutive odd numbers is 80. Find the product of the highest and lowest numbers out of those 4.

The correct option is A 391Let the numbers be a−3,a−1,a+1,a+3. Given: Sum = 80 =a−3+a−1+a+1+a+3=80⇒4a=80⇒a=20 Highest =20+3=23 Lowest =20−3=17 Product =17×23=391

The correct option is A 391
Let the numbers be $a - 3, a - 1, a + 1, a + 3$ .
Given: Sum = 80
$= a - 3 + a - 1 + a + 1 + a + 3 = 80 \Rightarrow 4 a = 80 \Rightarrow a = 20$
Highest $= 20 + 3 = 23$
Lowest $= 20 - 3 = 17$
Product $= 17 \times 23 = 391$