1
Question
Sum of 6 consecutive integers is 3. Find the sum of squares of those 6 integers.
Sum of 6 consecutive integers is 3. Find the sum of squares of those 6 integers.
Open in App
Solution
The correct option is A 19
Given: Sum =3
Let the integers be a,a+1,a+2,a+3,a+4,a+5=a+a+1+a+2+a+3+a+4+a+5=3=6a+15=3⇒6a=−12→a=−2
Thus, the numbers are −2,−1,0,1,2,3.
Sum of squares =4+1+0+1+4+9=19
Given: Sum =3
Let the integers be a,a+1,a+2,a+3,a+4,a+5=a+a+1+a+2+a+3+a+4+a+5=3=6a+15=3⇒6a=−12→a=−2
Thus, the numbers are −2,−1,0,1,2,3.
Sum of squares =4+1+0+1+4+9=19
Suggest Corrections
1
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
