Question

Sum of $9^{\circ }{45}^{\prime }{56}^{\prime \prime }$ and ${73}^{\circ }{8}^{\prime }{15}^{\prime \prime }$ is

• A. ${82}^{\circ }{53}^{\prime }{71}^{\prime \prime }$
• B. ${82}^{\circ }{53}^{\prime }{61}^{11}$
• C. ${82}^{\circ }{54}^{\prime }{11}^{\prime \prime }$
• D. ${81}^{\circ }{54}^{\prime }{11}^{\prime \prime }$

Answer 1

The correct option is C

${82}^{\circ }{54}^{\prime }{11}^{\prime \prime }$

$\begin{array}{c}{9}^{\circ }{45}^{\prime }{56}^{\prime \prime }\\ \underset{–}{+{73}^{\circ }{8}^{\prime }{15}^{\prime \prime }}\\ {82}^{\circ }{53}^{\prime }{71}^{\prime \prime }\end{array}$

Since ${60}^{\prime \prime }=1^{\prime }\therefore {71}^{\prime \prime }={60}^{\prime \prime }+{11}^{\prime \prime }=1^{\prime }{11}^{\prime \prime }$

${82}^{\circ }{53}^{\prime }{71}^{\prime \prime }={82}^{\circ }{54}^{\prime }{11}^{\prime \prime }$