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Question

Sum of a number and its reciprocal is 515. Then the required equation is

A
y2+1y=265
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B
5y226y+5=0
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C
y2+1y+265=0
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D
5y2+26y+5=0
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Solution

The correct option is B 5y226y+5=0
Let y be any number.

y+1y=515

y+1y=265

5(y2+1)=26y

5y2+5=26y

5y226y+5=0

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