Question

Sum of all angles of a square is

• A. ${90}^o$
• B. ${240}^o$
• C. ${120}^o$
• D. ${360}^o$

Answer 1

The correct option is D ${360}^o$

$\Rightarrow$ $\square ABCD$ is a square.

$\Rightarrow$ All four sides and angles of square are equal.

$\Rightarrow$ All four angles are right angle in square.

$\Rightarrow$ Sum of all angles of a square $ABCD=\angle A+\angle B+\angle C+\angle D$

$={90}^o+{90}^o+{90}^o+{90}^o$

$={360}^o$

$\therefore$ Sum of angles of square is ${360}^o$