Sum of all interior angles of a nonagon is

1260^o

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1080^o

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1460^o

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1620^o

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Solution

The correct option is
A

1260^o
Sum of all interior angles of a polygon with n sides = (n - 2) $\times$ 180^o

Therefore, sum of all interior angles of a nonagon

= (9 - 2) $\times$ 180^o
= 7 $\times$ 180^o
= 1260^o

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Similar questions

The measure of each interior angle of a regular nonagon is

1260^{o}

Sum of all the interior angles of a polygon is _____________ .

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