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Byju's Answer
Standard VI
Mathematics
Solving Equations x+a = b and x-a = b by Rearranging Terms
Sum of all th...
Question
Sum of all the seats in a theatre is in the form3n²÷2 + 125n÷2. If there are 2500 seats in that theatre, find the number of rows and number of seats in the last row.
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Solution
The
sum
of
all
seats
in
the
theatre
when
there
are
n
rows
is
3
n
2
2
+
125
n
2
As
,
there
are
2500
seats
in
the
theatre
,
therefore
3
n
2
2
+
125
n
2
=
2500
⇒
3
n
2
+
125
n
=
5000
⇒
3
n
2
+
125
n
-
5000
=
0
⇒
3
n
2
+
200
n
-
75
n
-
5000
=
0
⇒
n
3
n
+
200
-
25
3
n
+
200
=
0
⇒
n
-
25
3
n
+
200
=
0
⇒
n
=
25
,
-
200
3
Hence
,
the
number
of
rows
in
the
theatre
is
25
Now
the
number
of
seats
in
the
last
row
,
i
.
e
.
in
row
25
is
equal
to
the
(
Total
number
of
seats
in
the
25
rows
-
Total
number
of
seats
in
the
24
rows
)
=
1
2
3
25
2
+
125
25
-
1
2
3
24
2
+
125
24
=
2500
-
2364
=
136
.
Therefore
,
there
are
136
seats
in
the
last
row
.
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