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Question

Sum of all the values of x in the interval [0, 314] satisfying the equation sin x = 0 is

A
4950π
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B
5050π
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C
5151π
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D
none of these
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Solution

The correct option is B 5050π
sinx=0
x=nπ+0, where x[0,314]
Thus, x=0,π,2π,3π,....100π
Sum of all the values= 0+π+2π+...+100π
= π(1+2+3+...+100)
= π100×1012 Using formula of an AP, sum=n(2a+(n1)d)2
= 5050π

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