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Molecular Orbital Energy Diagrams

Sum of antibo...

Question

Sum of antibonding $π$ Electrons $(π^{*})$ in species $O_{2}, O_{2}^{-}$ and $O_{2}^{2 -}$ are

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Solution

Molecular orbitals electronic configuration of these species are :

$O^{- 2} (17 e^{-}) = σ 1 s^{2} σ^{} 1 s 2, σ 2 s^{2} σ^{} 2 s^{2}, σ 2 p_{x}^{2}, π 2 p_{y}^{2}, π 2 p_{z}^{2}, π^{} 2 p_{y}^{2} π^{} 2 p_{z}^{1}$

$O_{2} (16 e^{-}) = σ 1 s^{2} σ^{} 1 s 2, σ 2 s^{2} σ^{} 2 s^{2}, σ 2 p_{x}^{2}, π 2 p_{y}^{2}, π 2 p_{z}^{2}, π^{} 2 p_{y}^{1} π^{} 2 p_{z}^{1}$

$O_{2}^{- 2} (18 e^{-}) = σ 1 s^{2} σ^{} 1 s 2, σ 2 s^{2} σ^{} 2 s^{2}, σ 2 p_{x}^{2}, π 2 p_{y}^{2}, π 2 p_{z}^{2}, π^{} 2 p_{y}^{2} π^{} 2 p_{z}^{2}$

Hence, the number of antibonding electrons are 7,6 and 8 respectively and sum is $7 + 6 + 8 = 21$

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Similar questions

O_{2}^{-}, O_{2}

O_{2}^{- 2}

molecular species, the total number of antibonding electrons respectively are:

Q. What is the stability order of the following species?

O_{2}^{2 +}

O_{2}^{+}

O_{2}

O_{2}^{-}

O_{2}^{2 -}

Q. Which of the following species is/are diamagnetic
(I)

O_{2}^{+}

O_{2}

O_{2}^{-}

O_{2}^{2 -}

In $O_{2}^{-}$ , $O_{2} a n d O_{2}^{2 -}$ molecular species, the total number of anti-bonding electrons respectively are:

State True or False.

O_{2}, O_{2}^{-}

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are paramagnetic species.

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