Question

Sum of area of two square (square 1 and Square 2) is ${468m}^2$ and difference in the perimeter square is 24 . Find the side of Square 2

Answer 1

Let side of square $1$ be$:$ x meters

Perimeter of square $1$ $=4\times side=4x$

Now$,$ it is given by

Difference of perimeter of squares is $24m$

perimeter of square $1-$ perimeter of square $2=24$

$4x-$ perimeter of square $2=24$

$4x-24=$ perimeter of square $2$

perimeter of square $2=4x-24$

Now$,$

Perimeter of square $2=4x-24$

$4x$ $($side of square $2$ $)$ $=4x-24$

side of square $2$ $=\frac{4x-24}{4}=\frac{4\left(x-6\right)}{4}=x-6$