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Standard VI
Mathematics
Perimeter of Rectangle
Sum of areas ...
Question
Sum of areas of two squares is 468m². If the difference of their perimeter is 24m, find the sides of the two squares.
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Q.
Sum of the areas of two squares is 468
m
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. If the difference of their perimeters is 24 m, find the sides of the two squares.
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Sum of the areas of two square is
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Sum of the areas of two squares is 468
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Sum of the areas of two squares is 468
m
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. If the difference of their perimeters is 24 m, find the sides of the two squares.
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