Sum of basicity of $H_{3} {P O}_{4}, H_{3} {P O}_{3}, H_{3} {P O}_{2}$ is equal to:

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Solution

$H_{3} P O_{4}$ has three $O - H$ bonds so its basicity is 3.
$H_{3} P O_{3}$ has two $O - H$ bonds so its basicity is 2.
$H_{3} P O_{2}$ has one $O - H$ bond so its basicity is 1.

Total sum $= 3 + 2 + 1 = 6$

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