Question

Sum of digit of two number is 8. The digit in tens place is thrice the digit in unit place in unit place. Find the numbers?

Answer 1

62 is a number whose digits sum is 8(6+2) ,
digit at tens place 6ute
digit at ones place 2
digit at tens place is thrice the number at ones place, 6=3*2
solution:
assume our two digits as x and y
x is the number at tens place
y is the number at ones place
x=3y (given the number at tens place is thrice the number at ones place)
also given sum of the digits is 8
x+y=8 (substitute x=3y in this)
so 3y+y=8
that is 4y=8
therefore y=2
since x=3y then x=3*2 (got from above y=2)
hence x=6
so our number at tens place(x) is=6
number at ones place(y) is=2
so the number is 62