Sum of n terms of the series 2-8-18-32- isa nn-1 2b 2 n n -1c nn-1 2d 1

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Formula for Sum of n Terms of an AP

Sum of n term...

Question

Sum of n terms of the series $\sqrt{2} + \sqrt{8} + \sqrt{18} + \sqrt{32} + . . i s$

(a) $\frac{n (n + 1)}{2}$

(b) $2 n (n + 1)$

(c) $\frac{n (n + 1)}{\sqrt{2}}$

(d) 1

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Solution

In the given problem, we need to find the sum of terms for a given arithmetic progression,

So, here we use the following formula for the sum of n terms of an A.P.,

Where; a = first term for the given A.P.

d = common difference of the given A.P.

n = number of terms

Here,

Common difference of the A.P. (d) =

Number of terms (n) = n

First term for the given A.P. (a) =

So, using the formula we get,

Now, taking common from both the terms inside the bracket we get,

Therefore, the sum of first n terms for the given A.P. is. So, the correct option is (c).

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Sum of n terms of the series 2+8+18+32+..is (a) n (n + 1) 2 (b) 2n (n + 1) (c) n (n+1)2 (d) 1

Sum of n terms of the series $\sqrt{2} + \sqrt{8} + \sqrt{18} + \sqrt{32} + . . i s$

(a) $\frac{n (n + 1)}{2}$

(b) $2 n (n + 1)$

(c) $\frac{n (n + 1)}{\sqrt{2}}$

(d) 1