Question

Sum of opposite angles of an isosceles trapezium is

• A. ${90}^0$
• B. ${150}^0$
• C. ${120}^0$
• D. ${180}^0$

Answer 1

The correct option is D ${180}^0$

In an isosceles trapezium, the two top angles are equal to each other and the bottom two angles are equal to each other.
In isosceles trapezium ABCD,
Let $\angle A=\angle B=x$
And $\angle C=\angle D=y$


So, using angle sum property of a quadrilateral,
$x+x+y+y={360}^0$
$\Rightarrow x+y={180}^0$
Thus, the sum of opposite angles is equal to ${180}^0$.
So, the correct answer is option (d).