Seven years ago, Varun's age was 5 times the square of swatis age. Three years hence swatis age will be two fifth of Varun's age. Find their present ages if Varun's present age is x and swatis present age is y.

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Sum of the ages of three friends x years ago was y years. Then what will be the sum of their ages now?

The correct option is B 3x+yLet their present age be a,b,cSum of their present age =a+b+cTheir ages x years ago a−x,b−x,c−xSum =a+b+c−3xGiven a+b+c−3x=ya+b+c=y+3x=3x+ySo option A is correct.

Sum of the ages of three friends $x$ years ago was $y$ years. Then what will be the sum of their ages now?

The correct option is B $3 x + y$
Let their present age be $a, b, c$

Sum of their present age $= a + b + c$

Their ages $x$ years ago $a - x, b - x, c - x$

Sum $= a + b + c - 3 x$

Given $a + b + c - 3 x = y$

$a + b + c = y + 3 x = 3 x + y$

So option $A$ is correct.