Question

Sum of the areas of two squares is 640 m². If the difference of their perimeters is 64 m. Find the sides of the two squares.

Answer 1

Let the sides of the squares are x m and .Then

According to question,

Sum of the difference of their perimeter=64 m

….. (1)

And sum of the areas of square

….. (2)

Putting the value of x in equation (2) from equation (1)

or

Sides of the square never are negative.

Therefore, putting the value of x in equation (1)

Hence, sides of the square be and respectively.