Question

Sum of the digit of a two digit number is $9$. The number obtained by interchanging the digit exceed the given number by $27$, the number is

• A. $81$
• B. $45$
• C. $36$
• D. $27$

Answer 1

The correct option is C $36$

Let the number is $10x+y$

Now, $x+y=9$ $....\left(i\right)$

and $ATQ$ $10y+x-10x-y=27$

$y-x=3$ $....\left(ii\right)$

from equation $\left(i\right)\&\left(ii\right)$ $y=6$ and $x=3$

Hence, the number is $=10\times 3+6=36$