Sum of the digit of two digit number is 9.when we interchange the digit ,it is found that the resulting new number is greater than the original by 27.what is the 2 digit no ?
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Solution
Let the unit digit be y and tens digit be x Number formed = 10x + y Reverse number = 10y + x x + y = 9 (Given)…………………………eq1 10y + x = 10x + y + 27…………………….eq2 9y - 9x = 27 y - x = 3……………………………………..eq3 Solving eq1 and eq3 ,we get x = 3 and y = 6 Original Number = 36 Reversed Number = 63