Question

Sum of the digits of a 2-digit number is 9. When the digits are reversed, it is found that the resulting number is greater then the original number by 27. Find the number.

Answer 1

Let one's digit = x

And, ten's digit = y

Therefore, number is $10y+x$.

According to the question,

$x+y=9$ ....(1)

Also,

$10y+x+27=10x+y$

$x-y=3$ ......(2)

Solving equation 1 & 2, we get,

$x=6$ and $y=3$.

Hence, the original number is $10y+x=36$.