wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Sum of the last 30 coefficients in the expansion of (1+x)59, when expanded in ascending powers of x, is

A
229
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
228
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
60C30219
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
258
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 258
(1+x)59=59C0+59C1x+59C2x2+....59C59x59
Substituting x=1, we get
259=59C0+59C1+59C2+....59C59
259=2[59C0+59C1+59C2+....59C28]+59C29+59C30
259=2[59C0+59C1+59C2+....59C28+59C29]
Since 59C30=59C29
259=2[59C59+59C58+59C57+....59C31+59C30]
259=2(requiredsum)
Required sum =258

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Binomial Coefficients with Alternate Signs
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon