Sum of the series $1^{3} + 2^{3} + 3^{3} + . . .$ to $10$ terms is

2025

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3025

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4225

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2625

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Solution

The correct option is B $3025$
Sum of cubic terms from 1 to n is = $[n (n + 1) / 2]^{2}$
$= [10 (11) / 2]^{2} = 25 * 121 = 3025$
Option B

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