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Question

Sum of the series 3C14C2+5C36C4+ upto n terms is ( where Cr= nCr) is

A
1
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B
2
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C
2
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D
1
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Solution

The correct option is B 2
Let S=3C14C2+5C37C5+ upto n terms
=nr=1(1)r1 (r+2)Cr
=nr=1(1)r1rnCr+2nr=1(1)r1nCr
=nr=1(1)r1nn1Cr12nr=1(1)rnCr
=n.02nr=0nCr(1)r+2 nC0 (nr=0nCr(a)r=(1+a)n)
=2



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