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Byju's Answer
Standard XII
Mathematics
Series
Sum of the se...
Question
Sum of the series
567
,
189
,
63
,
.
.
.
upto
5
terms is
A
756
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B
847
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C
956
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D
849
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Solution
The correct option is
B
847
Here
189
567
=
1
3
and
63
189
=
1
3
So, it is G.P. with
r
=
1
3
Sum
=
a
(
r
n
−
1
)
r
−
1
⇒
S
5
=
567
(
(
1
3
)
5
−
1
)
1
3
−
1
=
847
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