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Question

Sum of the series nC1+25 nC2+352 nC3+ upto n terms is

A
n6n1
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B
6n1
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C
6n
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D
n6n
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Solution

The correct option is A n6n1
Let S=nC1+25 nC2+352 nC3+ upto n terms
=nr=15r1r nCr
=nr=15r1n n1Cr1
=nnr=1n1Cr15r1
=n(1+5)n1 (ns=0nCsar=(1+a)n)
=n6n1

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