Sum of the series S = 1 + 12(1 + 2) + 13(1 + 2 + 3) + 14 (1 + 2 + 3 + 4) + .........upto 20 terms is
110
111
115
116
We have
1k(1 + 2 + 3 + .......+ k) = 1k k(k+1)2 = k+12
Thus, S = 12[2 + 3 + 4 + .......21] = 102(2 + 21) = 115
Find the sum of the series s = 1 + 12(1 + 2) + 13(1 + 2 + 3) + 14(1 + 2 + 3 + 4) + .........upto 40 terms.
Sum of the series S=1+12(1+2)+13(1+2+3)+14(1+2+3+4)+ .....upto 19 terms is