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Question

Sum of the series
nk=0nkr=0(nk)(nkr) is

A
2n
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B
3n
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C
nr=0(1)rCr4r
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D
nr=0nCr2r
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Solution

The correct options are
B 3n
C nr=0(1)rCr4r
D nr=0nCr2r
k=nk=0nkr=0nCknkCr
Now nk0nkCr =2nr
Therefore
k=nk=0nCk2nk
=2nnC0+2n1nC1+...20nCn
=(2+1)n
=3n
This can re-written as
=(41)n
=r=nr=0(1)r4nr

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