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Question

Sum of three consecutive numbers is 39. Find the numbers.


A

10, 11, 12

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B

12, 13, 14

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C

13, 14, 15

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D

11, 12, 13

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Solution

The correct option is B

12, 13, 14


Let the smallest number be 'x'
So, the other two numbers are x+1 and x+2.
x+(x+1)+(x+2)=39 3x+3=39 3x=393 3x=36 x=363 x=12


Thus, the numbers are 12, 12+1, and 12+2
which is 12, 13 and 14.


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