Question

Sum of three consecutive numbers is 48. Find the numbers.

• A. 10,11,12
• B. 12,13,14
• C. 33,34,35
• D. 23,24,25

Answer 1

The correct option is C 33,34,35

Let the smallest number be '$x$'
So, the other two numbers are $x+1$ and $x+2$.
$x+(x+1)+(x+2)=48\Rightarrow 3x+3=48\Rightarrow 3x=45\Rightarrow x=\frac{45}{3}=15$
Thus, the numbers are 15,16 and 17.