Sum of three consecutive terms in an AP is 15 and their product is 0. The sequence is?
Both a and b are correct.
Given that three consecutive terms are in AP.
Let the terms be a - d, a, a + d.
Sum of these terms = 3a = 15.
So, a = 5.
Also their product (a−d)×a×(a+a)=a×(a2−d2)=0
Now a=5, so a2−d2=0
Therefore a=±d
d=5,−5
For d=5, the sequence is 0,5,10.
For d=-5, the terms are 10,5,0