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Question

Sum of three numbers is 432. First number is 3/4 times the second and third number is half of the second number. The smallest number is

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Solution

Given, the sum of three numbers is 432.

Let the second number be x, then,

3x4+x+x2=432

3x+4x+2x4=432

9x=432×4

x=192

Therefore,
Smallest number is x2=96

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