Question

Sum of three prime numbers is $40,$ then their product can be

• A. $217$
• B. $434$
• C. $450$
• D. $478$

Answer 1

The correct option is B $434$

Sum of three prime numbers is $40,$ which is even. So, $2$ must be one number as $2$ is only one even prime number.
Now, prime numbers which are less than $38$ are
$2,3,5,7,11,13,17,19,23,29,31,37$
Only $7+31$ gives $38.$
So, product $=2\times 7\times 31=434$