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Question

Sum of total number of chiral centres (X) and total number of pairs of enantiomers (Y) for following structure.
1065997_b406cc20ef14455b8b1f0cb125aa06a7.PNG

A
2
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B
3
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C
4
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D
8
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Solution

The correct option is B 2
No of chiral centre, n = 1 = X
where n is odd
Therefore, Pair of enantiomers are
= 2n12(n1)2 = Y
=210
=1
Therefore, X + Y = 1 + 1 = 2

1070954_1065997_ans_a8b36b09055543c38e323f8cef993db7.jpg

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