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Question
Sum of total number of chiral centres (X) and total number of pairs of enantiomers (Y) for following structure.
Sum of total number of chiral centres (X) and total number of pairs of enantiomers (Y) for following structure.
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Solution
The correct option is B 2
No of chiral centre, n = 1 = Xwhere n is oddTherefore, Pair of enantiomers are = 2n−1−2(n−1)2 = Y
=2−1−0 =1Therefore, X + Y = 1 + 1 = 2
No of chiral centre, n = 1 = X
where n is odd
Therefore, Pair of enantiomers are
= 2n−1−2(n−1)2 = Y
=2−1−0
=1
Therefore, X + Y = 1 + 1 = 2
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