Sum of two numbers is 20 and their difference is 5. Find the difference in their squares.

100

Open in App

Solution

The correct option is A
100

Let the numbers be a and b. Assume a > b.

(a+b)(a-b) = $a^{2} - b^{2}$ = 20 x 5 = 100.

Suggest Corrections

Similar questions

The sum of two squares of two numbers is 20 and their product is 2 .Find the difference between them

There are two numbers such that their difference is 3 and the difference of their squares is 69.

Find the sum of the numbers.

Find two natural numbers, the sum of whose squares is 25 times their sum and also equal to 50 times their difference.

4

316

If the sum and difference of two numbers are 20 and 8 respectively, then the difference of their squares is:

Join BYJU'S Learning Program