Question

Sum of two numbers is $29$ and one number exceeds another by $5$. Find the numbers.

Answer 1

We have a puzzle here. We don't know the numbers. We have to find them.
Let the smaller number '$x$', then the bigger number will be '$x+5$".
But it is given that sum of these two numbers is $29$
$\Rightarrow$ $x+x+5=29$
$\Rightarrow$ $2x+5=29$
$\therefore$ $2x=29-5$
$\therefore$ $2x=24$
$x=\frac{24}{2}$ (Transposing '$2$' to RHS)
$x=12$
Therefore smaller number $=x=12$ and
Bigger number $=x+5=12+5=17$

Thus the required numbers are $12$ and $17$