Sum of zeroes of the polynomial $a x^{2} + b x + c$ is:

\frac{c}{a}

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- \frac{b}{a}

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\frac{b}{c}

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\frac{a}{b}

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Solution

The correct option is D $- \frac{b}{a}$
We know that the roots of a quadratic equation $a x^{2} + b x + c = 0$ is
given by $\frac{- b \pm \sqrt{D}}{2 a}$

Here $D = \sqrt{b^{2} - 4 a c}$
Let these roots be denoted by $m$ and $n$
$m = \frac{- b + \sqrt{D}}{2 a}, n = \frac{- b - \sqrt{D}}{2 a}$
Sum of roots $m + n = \frac{- b + \sqrt{D}}{2 a} + \frac{- b - \sqrt{D}}{2 a}$
$m + n = \frac{- 2 b}{2 a} = - \frac{b}{a}$
so option b is true

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