- r -0 n n -3 r -1- n - r -1 n -2 C r is equal toA- 1-2nB- 1-3nC- 1-4nD- 1-2n-1

The correct option is A S=∑_r=0^n ( 1 2r/n r+1 )^nc_r/2^r=∑_r=0^n^nC_r/2^r ∑_r=0^n^nC_r 1/2^r 1=1/2^n ...

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Binomial Coefficients

∑ r =0 n n -3...

Question

$\sum_{r = 0}^{n} \frac{n - 3 r + 1}{n - r + 1} \frac{^{n} C_{r}}{2^{r}}$ is equal to

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